SQL删除重复数据
qq_37705525 人气:91 SQL去重
SQL中去除完全相同数据可以用distinct关键字,任意字段去重可以用group by,以下面的数据表为例。
2 distinct
存在两条完全相同的纪录,用关键字distinct就可以去掉
根据单个字段去重,能精确去重;
作用在多个字段时,只有当这几个字段的完全相同时,才能去重;
关键字distinct只能放在SQL语句中的第一个,才会起作用
一般用来返回不重复的记录条数,返回不重复的条数(去掉test重复的,就剩下6条)
3 group by
1. 查询根据名字去重后数据(名字相同取id值大的)
SELECT * FROM stu WHERE id IN (SELECT MAX(id) FROM stu GROUP BY `name`)
2. 删除名字相同数据(名字相同保留id值大的)
group by + count + max去掉重复数据
1)SELECT * FROM stu
2)加上group by 后,会将重复的数据去掉了
3) 条件(名字)是数量大于1的重复数据
SELECT `name` FROM stu GROUP BY `name` HAVING COUNT(`name`) > 1 #条件是数量大于1的重复数据 SELECT * FROM stu WHERE `name` IN( SELECT `name` FROM stu GROUP BY `name` HAVING COUNT(`name`)>1 )
4)查看某字段重复数据的id
SELECT id, COUNT(*) FROM stu GROUP BY NAME DESC HAVING(COUNT(*) > 0)
5)查询所有重复数据
SELECT * FROM stu WHERE NAME IN (SELECT `name` FROM stu GROUP BY `name` HAVING COUNT(`name`) > 1)
5) 去重
可以使用distinct去重(返回不重复的用户名)
删除多余的重复记录(name),只保留id最大的记录。
DELETE FROM stu WHERE id NOT IN ( SELECT a.id FROM ( SELECT MAX( id ) AS id FROM stu GROUP BY `name` )a )
或者
DELETE FROM stu WHERE `name` IN (SELECT `name` FROM (SELECT `name` FROM stu GROUP BY `name` HAVING COUNT(`name`)>1) e) AND id NOT IN (SELECT id FROM (SELECT MAX(id) AS id FROM stu GROUP BY `name` HAVING COUNT(`name`)>1) t) #查询显示重复的数据都是显示最前面的几条,因此不需要查询是否最小值
错误删除
DELETE FROM stu WHERE name
IN (SELECT name
FROM stu GROUP BY name
HAVING COUNT(name
)>1)
AND id NOT IN (SELECT MAX(id) FROM stu GROUP BY stu
HAVING COUNT(name
)>1)
原因是:不能将直接查处来的数据当做删除数据的条件,我们应该先把查出来的数据新建一个临时表,然后再把临时表作为条件进行删除功能
4 总结
去重后名字记录
SELECT `name` FROM stu GROUP BY NAME HAVING(COUNT(*) > 0)
2)
所有重复名字的记录
SELECT `name` FROM stu GROUP BY NAME HAVING COUNT(*) > 1
3)把所有重复的记录都删了
DELETE FROM stu WHERE
name
IN
(SELECTname
FROM stu GROUP BYname
HAVING COUNT(*)>1)
无法在删除时同时查询这张表,这个问题只在MySQL中出现,oracle没有。怎么解决?我们只需要在查出结果以后加一张中间表。让执行器认为我们要查的数据不是来自正在删的这张表就可以了。
DELETE FROM stu WHERE `name` IN (SELECT a.name FROM (SELECT `name` FROM stu GROUP BY `name` HAVING COUNT(*)>1) a)
所有重复数据都删除, 就剩王五一条数据了
4) 现在删除所有重复数据数据做完了,考虑怎么保留重复数据中id最小的。只需要在删除时让删除该条的记录id不在重复数据id最小的当中就可以了。
DELETE FROM stu WHERE `name` IN (SELECT a.name FROM (SELECT `name` FROM stu GROUP BY `name` HAVING COUNT(*)>1) a) AND id NOT IN (SELECT b.id FROM (SELECT MIN(id) id FROM stu GROUP BY `name` HAVING COUNT(*)>1) b);
还有简单办法 算出去重后所有数据(保留最小ID),然后删除id不在该数组里的
DELETE FROM stu WHERE id NOT IN (SELECT t.id FROM (SELECT MIN(id) AS id FROM stu GROUP BY `name`)t)
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