java 根据身份证号码判断出生日期、性别、年龄的示例
Marydon 人气:01.情景展示
如何根据SFZ号,计算出出生日期、性别、年龄?
2.解决方案
从网上找的别人的,因为并没有实际用到,所以并未对其优化!
/** * 通过SFZ号码获取出生日期、性别、年龄 * @param certificateNo * @return 返回的出生日期格式:1990-01-01 性别格式:F-女,M-男 */ public static Map<String, String> getBirAgeSex(String certificateNo) { String birthday = ""; String age = ""; String sexCode = ""; int year = Calendar.getInstance().get(Calendar.YEAR); char[] number = certificateNo.toCharArray(); boolean flag = true; if (number.length == 15) { for (int x = 0; x < number.length; x++) { if (!flag) return new HashMap<String, String>(); flag = Character.isDigit(number[x]); } } else if (number.length == 18) { for (int x = 0; x < number.length - 1; x++) { if (!flag) return new HashMap<String, String>(); flag = Character.isDigit(number[x]); } } if (flag && certificateNo.length() == 15) { birthday = "19" + certificateNo.substring(6, 8) + "-" + certificateNo.substring(8, 10) + "-" + certificateNo.substring(10, 12); sexCode = Integer.parseInt(certificateNo.substring(certificateNo.length() - 3, certificateNo.length())) % 2 == 0 ? "F" : "M"; age = (year - Integer.parseInt("19" + certificateNo.substring(6, 8))) + ""; } else if (flag && certificateNo.length() == 18) { birthday = certificateNo.substring(6, 10) + "-" + certificateNo.substring(10, 12) + "-" + certificateNo.substring(12, 14); sexCode = Integer.parseInt(certificateNo.substring(certificateNo.length() - 4, certificateNo.length() - 1)) % 2 == 0 ? "F" : "M"; age = (year - Integer.parseInt(certificateNo.substring(6, 10))) + ""; } Map<String, String> map = new HashMap<String, String>(); map.put("birthday", birthday); map.put("age", age); map.put("sexCode", sexCode); return map; }
根据SFZ号提取出生日期
// 出生日期 String birthday = ""; // SFZ号不为空 if (sfzh.length() == 15) { birthday = "19" + sfzh.substring(6, 8) + "-" + sfzh.substring(8, 10) + "-" + sfzh.substring(10, 12); } else if (sfzh.length() == 18) { birthday = sfzh.substring(6, 10) + "-" + sfzh.substring(10, 12) + "-" + sfzh.substring(12, 14); }
写在最后
哪位大佬如若发现文章存在纰漏之处或需要补充更多内容,欢迎留言!!!
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