基于C语言实现钻石棋游戏的示例代码
编程小鱼六六六 人气:0游戏规则
这是一个单人钻石棋游戏,游戏中有两种颜色的棋子:红色和绿色。每个玩家在游戏进行中轮流选择一个空格,并在该空格上放置自己的棋子。游戏的目的是尽可能地连成一条长的直线,使该直线的颜色与你的棋子颜色相同。如果所有格子都被填满,游戏将结束。最后,显示游戏结束的消息。注意:不能在已经被占用的格子上放置棋子。游戏胜利条件
胜利的条件是在棋盘上连成一条长度大于或等于5个格子的直线,且该直线上所有格子的颜色都相同。当一方玩家连成胜利直线后,游戏将结束并显示游戏结束的消息。
实现代码
#define _CRT_SECURE_NO_WARNINGS #include <graphics.h> #include <conio.h> #include <stdlib.h> #include <time.h> #define ROWS 8 #define COLUMNS 8 #define CELL_SIZE 50 int board[ROWS][COLUMNS]; void init_board() { for (int i = 0; i < ROWS; i++) { for (int j = 0; j < COLUMNS; j++) { board[i][j] = rand() % 3; } } } void draw_board() { for (int i = 0; i <= ROWS; i++) { line(0, i * CELL_SIZE, COLUMNS * CELL_SIZE, i * CELL_SIZE); } for (int i = 0; i <= COLUMNS; i++) { line(i * CELL_SIZE, 0, i * CELL_SIZE, ROWS * CELL_SIZE); } for (int i = 0; i < ROWS; i++) { for (int j = 0; j < COLUMNS; j++) { if (board[i][j] == 1) { setfillcolor(RED); fillcircle(j * CELL_SIZE + CELL_SIZE / 2, i * CELL_SIZE + CELL_SIZE / 2, CELL_SIZE / 2 - 5); } else if (board[i][j] == 2) { setfillcolor(GREEN); fillcircle(j * CELL_SIZE + CELL_SIZE / 2, i * CELL_SIZE + CELL_SIZE / 2, CELL_SIZE / 2 - 5); } } } } bool check_valid_move(int row, int col) { return row >= 0 && row < ROWS && col >= 0 && col < COLUMNS && board[row][col] == 0; } bool make_move(int row, int col, int player) { if (check_valid_move(row, col)) { board[row][col] = player; return true; } return false; } bool check_game_over() { for (int i = 0; i < ROWS; i++) { for (int j = 0; j < COLUMNS; j++) { if (board[i][j] == 0) { return false; } } } return true; } int check_win(int row, int col) { int i, j, color = board[row][col]; // 检查该点所在行是否有5个相连的棋子 for (i = row - 4; i <= row; i++) { if (i >= 0 && i + 4 < ROWS) { int count = 0; for (j = i; j <= i + 4; j++) { if (board[j][col] == color) { count++; } } if (count == 5) { return 1; } } } // 检查该点所在列是否有5个相连的棋子 for (i = col - 4; i <= col; i++) { if (i >= 0 && i + 4 < COLUMNS) { int count = 0; for (j = i; j <= i + 4; j++) { if (board[row][j] == color) { count++; } } if (count == 5) { return 1; } } } // 检查该点所在主对角线是否有5个相连的棋子 for (i = row - 4, j = col - 4; i <= row && j <= col; i++, j++) { if (i >= 0 && i + 4 < ROWS && j >= 0 && j + 4 < COLUMNS) { int count = 0; int x, y; for (x = i, y = j; x <= i + 4 && y <= j + 4; x++, y++) { if (board[x][y] == color) { count++; } } if (count == 5) { return 1; } } } // 检查该点所在副对角线是否有5个相连的棋子 for (i = row - 4, j = col + 4; i <= row && j >= 0; i++, j--) { if (i >= 0 && i + 4 < ROWS && j >= 0 && j - 4 < COLUMNS) { int count = 0; int x, y; for (x = i, y = j; x <= i + 4 && y >= j - 4; x++, y--) { if (board[x][y] == color) { count++; } } if (count == 5) { return 1; } } } return 0; } int main() { srand(time(0)); init_board(); initgraph(COLUMNS * CELL_SIZE + 100, ROWS * CELL_SIZE + 100); draw_board(); settextcolor(DARKGRAY); settextstyle(20,0,_T("宋体")); outtextxy(COLUMNS * CELL_SIZE - 200, ROWS * CELL_SIZE+20, "公众号:C语言研究"); int player = 1; ExMessage m; while (!check_game_over()) { m = getmessage(EX_MOUSE | EX_KEY); if (m.message == WM_LBUTTONDOWN) { int x = m.x; int y = m.y; int row = y / CELL_SIZE; int col = x / CELL_SIZE; if (make_move(row, col, player)) { draw_board(); if (check_win(row, col)) { settextstyle(64, 0, "黑体"); const char *player_string; if (player == 1) { player_string = "红棋"; } else { player_string = "绿棋"; } char win_message[100]; strcpy(win_message, "玩家"); strcat(win_message, player_string); strcat(win_message, "获胜!"); outtextxy(COLUMNS * CELL_SIZE / 2 - 100, ROWS * CELL_SIZE / 2 - 50, win_message); _getch(); closegraph(); return 0; } player = player == 1 ? 2 : 1; } } } settextstyle(64, 0, "黑体"); outtextxy(COLUMNS * CELL_SIZE / 2 - 100, ROWS * CELL_SIZE / 2 - 100, "游戏结束"); _getch(); closegraph(); return 0; }
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