C语言代码实现井字棋游戏
lijiao 人气:0井字棋是一个很常见的小游戏。要求对战双方在一个“井”形的棋盘里分别下“*”棋子或者“#”棋子,谁先连成3个,谁就赢。
本次使用C语言来实现这个小游戏。
由于使用函数较多,所以采用多文件的方式方便梳理代码思路。
本次一共有三个文件:
**
game.h:
包含了game.c文件中函数的声明和库函数的声明。**
#pragma once
#define ROW 3
#define COL 3
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
void InitBoard(char board [ROW][COL], int row, int col); //初始化棋盘
void DisplayBoard(char board [ROW][COL], int row, int col); //打印棋盘
void PlayerBoard(char board [ROW][COL], int row, int col); //玩家走
void ComputerBoard(char board [ROW][COL], int row, int col);//电脑走
char IsWin(char board [ROW][COL], int row, int col); //结果判断
game.c:
包含游戏过程中关键函数的函数主体。
#define _CRT_SECURE_NO_WARNINGS
#include"game.h"
void InitBoard(char board[ROW][COL], int row, int col)
{
//初始化棋盘
int i = 0;
for (i = 0; i < row; i++)
{
int j = 0;
for (j = 0; j < col; j++)
board [i][j] = ' ';
}
}
void DisplayBoard(char board [ROW][COL], int row, int col)
{
//打印棋盘
int i = 0;
for (i = 0; i < row; i++)
{
int j = 0;
for (j = 0; j < col; j++)
{
printf(" %c ", board [i][j]);
if (j < col - 1)
printf("|");
}
printf("\n");
if (i < row - 1)
{
for (j = 0; j < col; j++)
{
printf("---");
if (j < col - 1)
printf("|");
}
printf("\n");
}
}
}
void PlayerBoard(char board [ROW][COL], int row, int col)
{
int x = 0, y = 0;
while (1)
{
printf("输入棋子坐标->");
scanf("%d%d", &x, &y);
if (x > 0 && x <= row && y > 0 && y <= col)
{
if (board [x - 1][y - 1] == ' ')
{
board [x - 1][y - 1] = '*';
break;
}
else
{
printf("此位置已有棋子!请重新输入。\n");
}
}
else
{
printf("输入错误!请重新输入。\n");
}
}
}
void ComputerBoard(char board [ROW][COL], int row, int col)
{
int x = 0, y = 0;
while (1)
{
x = rand() % row;
y = rand() % col;
if (board [x][y] != ' ')
{
continue;
}
else
{
board [x][y] = '#';
break;
}
}
}
int IsFull(char board [ROW][COL], int row, int col)
{
int i = 0;
for (i = 0; i < row; i++)
{
int j = 0;
for (j = 0; j < col; j++)
{
if (board [i][j] == ' ')
return 0;
}
}
return 1;
}
char IsWin(char board [ROW][COL], int row, int col)
{
int i = 0;
//行
for (i = 0; i < row; i++)
{
if (board [i][0] == board [i][1] && board [i][1] == board [i][2] && board [i][0] != ' ')
return board [i][0];
}
//列
for (i = 0; i < col; i++)
{
if (board [0][i] == board [1][i] && board [1][i] == board [2][i] && board [0][i] != ' ')
return board [0][i];
}
//对角线
if (board [0][0] == board [1][1] && board [1][1] == board [2][2] & board [1][1] != ' ')
return board [1][1];
if (board [2][0] == board [1][1] && board [1][1] == board [0][2] & board [1][1] != ' ')
return board [1][1];
//是否平局
if (IsFull(board, row, col))
return 'Q';//平局
return 'C';//继续
}
test.c:
main函数和游戏的大概流程。
#define _CRT_SECURE_NO_WARNINGS
#include"game.h"
void Menu()
{
printf("*******************************\n");
printf("********** 1、play **********\n");
printf("********** 0、quit **********\n");
printf("*******************************\n");
}
void game()
{
char board [ROW][COL];
InitBoard(board, ROW, COL);
DisplayBoard(board, ROW, COL);
char ret = 0;
srand((unsigned int) time(NULL));
while (1)
{
printf("玩家走\n");
PlayerBoard(board, ROW, COL);
DisplayBoard(board, ROW, COL);
ret = IsWin(board, ROW, COL);
if (ret != 'C')
break;
printf("电脑走\n");
ComputerBoard(board, ROW, COL);
DisplayBoard(board, ROW, COL);
ret = IsWin(board, ROW, COL);
if (ret != 'C')
break;
}
if (ret == '*')
printf("玩家胜利!\n");
else if (ret == '#')
printf("电脑胜利!\n");
else
printf("平局!\n");
}
int main()
{
//三子棋
int input = 1;
while (input)
{
Menu();
printf("输入1开始游戏,输入0退出游戏。\n请输入->");
scanf("%d", &input);
switch(input)
{
case 1:
game();
printf("开始游戏\n");
break;
case 0:
printf("游戏结束\n");
break;
default:
printf("非法输入,请重试!\n");
}
}
return 0;
}
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