C++有向图邻接表 C++实现有向图邻接表的构建
GetoWork 人气:0数据结构里面的一道基础题,分享下自己的写法,验证可跑。
#include<iostream> #include<string> const int MAX = 20; using namespace std; struct ArcNode { //弧结点 int adjvex = -1; //所指顶点位置 ArcNode *nextarc = nullptr; //下一条狐指针 size_t info = 0; //弧信息 }; struct VNode { //顶点 string data = "0"; ArcNode *firstarc = nullptr; //第一条依附该顶点的弧的指针 }; struct Graph { //图结构 VNode vertices[MAX]; //全部顶点 int vexnum, arcnum; //顶点数和弧数 Graph(int m, int n) :vexnum(m), arcnum(n) {}; Graph() :vexnum(0), arcnum(0) {}; }; int main() { int vnum, anum, tempanum = 0; cout << "输入顶点数:"; cin >> vnum; cout << "输入弧数:"; cin >> anum; cout << "\n\n"; Graph G(vnum, anum); for (int i = 0; i != vnum; ++i) { cout << "输入结点" << i << "的信息:"; cin >> G.vertices[i].data; if (tempanum != anum) cout << "输入依靠此结点的弧的信息(输入-1以停止):\n"; else cout << "已输入所有弧的信息!\n"; bool first = true; ArcNode *p, *temp; for (int j = 0; (j != anum) && (tempanum != vnum); ++j) { int pointto; cout << "输入弧" << tempanum << "所指向的顶点位置:"; cin >> pointto; if (pointto == -1) break; else { ++tempanum; if (first == true) { first = false; G.vertices[i].firstarc = new ArcNode; G.vertices[i].firstarc->adjvex = pointto; p = G.vertices[i].firstarc; } else { temp = new ArcNode; temp->adjvex = pointto; p->nextarc = temp; p = temp; } } } cout << endl; } for (int i = 0; i != anum; ++i) { cout << "顶点" << i << ": |" << G.vertices[i].data << "|"; if (G.vertices[i].firstarc) { cout << " -> " << G.vertices[i].firstarc->adjvex; auto pt = G.vertices[i].firstarc->nextarc; while (pt) { cout << " -> " << pt->adjvex; pt = pt->nextarc; } cout << "-> ^"; } else cout << " -> ^"; cout << endl; } return 0; }
由于只是单纯构建基本的无权值有向图邻接表,里面的弧结构中弧信息未利用到。
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