亲宝软件园·资讯

展开

C语言实现三子棋

人气:1

题目:C语言实现三子棋

问题分析:首先用到数组,存储信息。棋盘的信息和棋子的信息
打印棋盘
读取棋子的位置
判断是否连子
打印棋盘
然后重复

代码如下:

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<stdlib.h>
//数组沙盘
char Global_Gobang[10][10];
int Global_line, Global_pow;
int Global_player;
int Global_Count=0;
//初始化棋盘
void Initi_Gobang(){
 for (int i = 0; i < 10; i++){
 for (int j = 0; j < 10; j++){
 Global_Gobang[i][j] = '+';
 }
 }
}
//画出棋盘
void Draw_Gobang(){
 for (int i = 0; i < 10; i++){
 for (int j = 0; j < 10; j++){
 printf("%c ", Global_Gobang[i][j]);
 }
 printf("\n");
 }
}
//在位置上下棋
void Play_Gobang(int player, int line, int row){
 // int flag= Check_Gobang();

 while (player == 0 || player == 1)
 {
 if (player == 0)
 {
 if (Global_Gobang[line - 1][row - 1] != 'o' && Global_Gobang[line - 1][row - 1] != '@'){
 Global_Gobang[line - 1][row - 1] = 'o';
 break;
 } 
 else
 {
 printf("这个位置已经有棋子,请重新输入");
 scanf("%d%d", &Global_line, &Global_pow);
 Play_Gobang(Global_player, Global_line, Global_pow);
 break;
 }
 }
 else if (player == 1)
 {
 if (Global_Gobang[line - 1][row - 1] != 'o' && Global_Gobang[line - 1][row - 1] != '@'){
 Global_Gobang[line - 1][row - 1] = '@';
 break;
 } 
 else
 {
 printf("这个位置已经有棋子,请重新输入");
 scanf("%d%d", &Global_line, &Global_pow);
 Play_Gobang(Global_player, Global_line, Global_pow);
 break;
 }
 }

 }
}
//输入棋子的位置
void Input_Gobang(){
 if (Global_player == 1){
 printf("请1号玩家输入棋子的位置");
 }
 else if (Global_player == 0)
 {
 printf("请2号玩家输入棋子的位置");
 }
 scanf("%d %d", &Global_line, &Global_pow);
 system("cls");//刷新界面
}
int Check_Gobang(){
 //i j 为行列的表示,flag为判断棋盘是否满了的标志,flag=0,代表满了
 int i, j, flag = 0;
 //判断行是否成立
 for (i = 0; i < 10; i++)
 for (j = 0; j < 8; j++)
 if (Global_Gobang[i][j]!='+' && Global_Gobang[i][j] == Global_Gobang[i][j + 1] && Global_Gobang[i][j] == Global_Gobang[i][j + 2])
 return 1;
 //判断列是否成立
 for (i = 0; i < 10; i++)
 for (j = 0; j < 8; j++)
 if (Global_Gobang[i][j] != '+' &&Global_Gobang[j][i] == Global_Gobang[j + 1][i] && Global_Gobang[i][j] == Global_Gobang[j + 2][i])
 return 1;
 //判断主对角线是否成立1
 for (i = 0; i < 8; i++)
 for (j = 0; j < 8; j++)
 if (Global_Gobang[i][j] != '+' &&Global_Gobang[j][i] == Global_Gobang[j + 1][i + 1] && Global_Gobang[i][j] == Global_Gobang[j + 2][i + 2])
 return 1;
 //判断副对角线是否成立2
 for (i = 2; i < 10; i++)
 for (j = 2; j < 10; j++)
 if (Global_Gobang[i][j] != '+' &&Global_Gobang[j][i] == Global_Gobang[j - 1][i - 1] && Global_Gobang[i][j] == Global_Gobang[j - 2][i - 2])
 return 1;
 for (i = 0; i < 10; i++){
 for (j = 0; j < 10; j++){
 if (Global_Gobang[i][j] == '+')
 flag = 1;
 }
 }
 if (flag == 0)
 return 0;
}
//
int Playing_Gobang(){
 Global_Count++;
 if (Global_Count % 2 == 1)
 Global_player = 1;
 else
 Global_player = 0;
 if (Check_Gobang() == 1){
 if (Global_player == 1){
 printf("玩家2号赢得胜利,游戏结束\n");
 return 1;
 }
 else{
 printf("玩家1号赢得胜利,游戏结束\n");
 return 1;
 }
 }
 else if (Check_Gobang() == 0)
 {
 printf("棋盘已满,游戏结束\n");
 }
 Input_Gobang();
 Play_Gobang(Global_player, Global_line, Global_pow);
 Draw_Gobang();
}

int main(){
 Initi_Gobang();
 Draw_Gobang();
 while (Global_Count<=100)
 if (Playing_Gobang() == 0 || Playing_Gobang() == 1)
 break;
 system("pause");
 return 0;
}

结果如下:

更多有趣的经典小游戏实现专题,分享给大家:

C++经典小游戏汇总

python经典小游戏汇总

python俄罗斯方块游戏集合

JavaScript经典游戏 玩不停

java经典小游戏汇总

javascript经典小游戏汇总

您可能感兴趣的文章:

加载全部内容

相关教程
猜你喜欢
用户评论