Python3旋转矩阵图像算法 Python3实现的旋转矩阵图像算法示例
zhenghaitian 人气:0本文实例讲述了Python3实现的旋转矩阵图像算法。分享给大家供大家参考,具体如下:
问题:
给定一个 n × n 的二维矩阵表示一个图像。
将图像顺时针旋转 90 度。
方案一:先按X轴对称旋转, 再用zip()解压,最后用list重组。
# -*- coding:utf-8 -*- #! python3 class Solution: def rotate(self, matrix): """ :type matrix: List[List[int]] :rtype: void Do not return anything, modify matrix in-place instead. """ matrix[:] = map(list, zip(*matrix[: : -1])) return matrix if __name__ == '__main__': # 测试代码 matrix = [ [1,2,3,4], [5,6,7,8], [9,10,11,12], [13,14,15,16] ] solution = Solution() result = solution.rotate(matrix) print(result)
运行结果:
[[13, 9, 5, 1], [14, 10, 6, 2], [15, 11, 7, 3], [16, 12, 8, 4]]
方案二:找到规律,用原矩阵数据 赋值
# -*- coding:utf-8 -*- #! python3 class Solution: def rotate(self, matrix): """ :type matrix: List[List[int]] :rtype: void Do not return anything, modify matrix in-place instead. """ m = matrix.copy() n = len(matrix) for i in range(n): matrix[i] = [m[j][i] for j in range(n - 1, -1, -1)] return if __name__ == '__main__': # 测试代码 matrix = [ [1,2,3,4], [5,6,7,8], [9,10,11,12], [13,14,15,16] ] solution = Solution() result = solution.rotate(matrix) print(result)
运行结果:
[[13, 9, 5, 1], [14, 10, 6, 2], [15, 11, 7, 3], [16, 12, 8, 4]]
希望本文所述对大家Python程序设计有所帮助。
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