vue.js异步上传文件前后端实现代码

时间:2020-05-16 qkabcd 人气:0

本文实例为大家分享了vue.js异步上传文件的具体代码，供大家参考，具体内容如下

上传文件前端代码如下：

<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8"/>
  <title></title>
  <meta charset="utf-8" />
  <script src="../js/vue.js"></script>
  <script src="../js/vue-resource.js"></script>
  <script src="../asset/js/jquery.js"></script>

</head>
<body>
  <div id="app">
    <input type="file" @change="getFile($event)" /><button @click="upload">上传</button>
    <div>{{ result }}</div>
    <div v-show="uping==1">正在上传中</div>
  </div>

<script>
  new Vue({
    el: '#app',
    data: {
      upath: '',
      result: '',
      uping:0
    },
    methods: {
      upload: function () {
        //console.log(this.upath);
        var zipFormData = new FormData();
        zipFormData.append('filename', this.upath);//filename是键，file是值，就是要传的文件，test.zip是要传的文件名
        let config = { headers: { 'Content-Type': 'multipart/form-data' } };
        this.uping = 1;
        this.$http.post('http://localhost:42565/home/up', zipFormData,config).then(function (response) {
          console.log(response);
          console.log(response.data);
          console.log(response.bodyText);
          
          var resultobj = response.data;
          this.uping = 0;
          this.result = resultobj.msg;
        });
      },

      getFile: function (even) {
        this.upath = event.target.files[0];
      },
    }
  });
</script>
</body>
</html>

后端处理代码如下asp.net mvc的：

public ActionResult Up()
    {
      string msg = string.Empty;
      string error = string.Empty;
      string result = string.Empty;
      string filePath = string.Empty;
      string fileNewName = string.Empty;
      var files = Request.Files;
      if (files.Count > 0)
      {
        //设置文件名
        fileNewName = DateTime.Now.ToString("yyyyMMddHHmmssff") + "_" + System.IO.Path.GetFileName(files[0].FileName);
        //保存文件
        files[0].SaveAs(Server.MapPath("~/Uploads/" + fileNewName));
        Thread.Sleep(10 * 1000);
      }
      return Json(new { msg = "上传成功", newfilename = fileNewName }, JsonRequestBehavior.AllowGet);
    }

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