js中根据字数截取字符串，不能截断url

复制代码 代码如下:

String.prototype.sizeAt = function(){
var nLen = 0;
for(var i = 0, end = this.length; i<end; i++){
nLen += this.charCodeAt(i)>128?2:1;
}
return nLen;
};
String.prototype.cutStr = function(n, sCut){
if(this.sizeAt() <= n){
return this;
}
sCut = sCut || "";
var max = n-sCut.sizeAt();
var nLen = 0;
var s = this;
for(var i =0,end = this.length;i<end;i++){
nLen += this.charCodeAt(i)>128?2:1;
if(nLen>max){
s = this.slice(0,i);
s += sCut;
break;
}
}
return s.toString();
};
String.prototype.cutStrButUrl = function(n, sCut){
if(this.sizeAt() <=n){
return this.toString();
}
sCut = sCut || "";
var max = n-sCut.sizeAt();
var s = this;
//查找所有包含的url
var aUrl = s.match(/https?:\/\/[a-zA-Z0-9]+(\.[a-zA-Z0-9]+)+([-_A-Z0-9a-z\$\.\+\!\*\/,:;@&=\?\~\#\%]*)*/gi);
//当第max个字符刚好在url之间时，bCut会被设置为flase;
var bCut = true;
if(aUrl){
//对每个url进行判断
for(var i=0, endI = aUrl.length;i<endI;i++){
var sUrl = aUrl[i];
//可能出现两个相同url的情况
var aP = s.split(sUrl);
var nCurr = 0;
var nLenURL = sUrl.sizeAt();
var sResult = "";
for(j = 0, endJ = aP.length; j<endJ; j++){
nCurr +=aP[j].sizeAt();
sResult +=aP[j];
sResult += sUrl;
//当前字数相加少于max但添加url超过max：即会截到url
if(nCurr < max && nCurr + nLenURL>max){
s = sResult + sCut;
bCut = false;
break;
}
nCurr += nLenURL;
}
if(bCut === false){
break;
}
};
}
if(bCut){
s = s.cutStr(n, sCut);
}
return s.toString();
};
console.log('正常截取20个字符'.cutStrButUrl(20,'......'));
console.log('正常截取20个字符,但我超了'.cutStrButUrl(20,'......'));
console.log('有url的字符串http://www.baidu.com你能截取到吗？'.cutStrButUrl(20,'......'));
console.log('http://www.baidu.com有两个相同url的字符串http://www.baidu.com好吗？'.cutStrButUrl(51, '......'));