python计算列表

时间:2022-09-28 Python热爱者人气:0

插入代码块

使用sum函数：

numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
print(sum(numbers))

使用reduce函数：

# 方式1
from functools import reduce

numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
results = reduce(lambda x, y: x + y, numbers)
print(results)

# 方式2
from operator import add
from functools import reduce
numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
results = reduce(add, numbers)
print(results)

使用for循环：

numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
result = 0
for number in numbers:
    result += number
print(result)

使用递归：

numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
def cal(list1, size):
    if size:
        return list1[size - 1] + cal(list1, size - 1)
    return size
print(cal(numbers, len(numbers)))

列表乘积计算

使用for循环：

numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
result = 1
for number in numbers:
    result *= number
print(result)

使用reduce函数：

# 方式1
from functools import reduce
numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
results = reduce(lambda x, y: x * y, numbers)
print(results)

# 方式2
from operator import mul
from functools import reduce
numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
results = reduce(mul, numbers)
print(results)

使用递归函数：

numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
def cal(list1, size):
    if size == 0:
        return 1
    return list1[size - 1] * cal(list1, size - 1)
print(cal(numbers, len(numbers)))

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