Mysql查询时间区间

时间:2022-06-03 码奴生来只知道前进~ 人气:0

1、查询时间区间日期列表，不会由于数据表数据影响

select a.date 
from (
    select curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a) + (1000 * d.a) ) DAY as date
    from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
    cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
    cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c
    cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as d
) a
where a.date between '2020-01-20' and '2021-12-24' ORDER BY a.date asc

tips：如果要查询当前日期后面的数据 curdate()改为截止日期就好

2、创建视图可以公共使用

CREATE VIEW v_digits AS
  SELECT 0 AS digit UNION ALL
  SELECT 1 UNION ALL
  SELECT 2 UNION ALL
  SELECT 3 UNION ALL
  SELECT 4 UNION ALL
  SELECT 5 UNION ALL
  SELECT 6 UNION ALL
  SELECT 7 UNION ALL
  SELECT 8 UNION ALL
  SELECT 9;
 
CREATE VIEW v_numbers AS
  SELECT
    ones.digit + tens.digit * 10 + hundreds.digit * 100 + thousands.digit * 1000 AS number
  FROM
    v_digits as ones,
    v_digits as tens,
    v_digits as hundreds,
    v_digits as thousands;
		
-- 生成的日期格式为  yyyy-MM-dd		
CREATE VIEW v_dates AS
  SELECT
    SUBDATE(CURRENT_DATE(), number) AS date
  FROM
    v_numbers
  UNION ALL
  SELECT
    ADDDATE(CURRENT_DATE(), number + 1) AS date
  FROM
    v_numbers;
 
-- 生成的日期格式为 yyyy-MM
CREATE VIEW v_months AS
  SELECT
    DATE_FORMAT(SUBDATE(CURRENT_DATE(), INTERVAL number MONTH),'%Y-%m')  AS date
  FROM
    v_numbers
  UNION ALL
  SELECT
    DATE_FORMAT(ADDDATE(CURRENT_DATE(), INTERVAL number+1 MONTH),"%Y-%m") AS date
  FROM
    v_numbers;

3、创建为视图之后，可以通过视图查询时间区间列表日期

SELECT
  date
FROM
  v_dates
WHERE
  date BETWEEN '2020-01-20' AND '2021-01-24'
ORDER BY
  date asc

4、查询时间区间按月

select DATE_FORMAT(str_to_date (a.Date,'%Y-%m-%d'),"%Y-%m") as Date 
from (
    select '2011-12-24' - INTERVAL (a.a + (10 * b.a) + (100 * c.a) + (1000 * d.a) ) MONTH as Date
    from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
    cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
    cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c
    cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as d
) a
where a.Date between '2010-01-20' and '2011-12-24' ORDER BY a.Date asc;

附：在对mysql的时间进行区间查询的时候出现的问题

<if test="searchcondition.starttime!=null">
    <![CDATA[ and select_data.data_time  >= #{searchcondition.starttime,jdbcType=TIMESTAMP} ]]>
</if>

<if test="searchcondition.stoptime!=null">
    <![CDATA[ and select_data.data_time <= #{searchcondition.stoptime,jdbcType=TIMESTAMP} ]]>
</if>

在test中不能使用searchcondition.stoptime!=’ ‘这个判断会报错,上面的是标准的时间查询,自己做的时候总是会加上!=’ ‘这个条件.所以总是报错,记录一下.

总结

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