Python炸金花游戏
Python进阶者 人气:0前言
《诈金花》又叫三张牌,是在全国广泛流传的一种民间多人纸牌游戏。比如JJ比赛中的诈金花(赢三张),具有独特的比牌规则。游戏过程中需要考验玩家的胆略和智慧。--《百度百科》 前几天在交流群里边,有个叫【^-^】的粉丝分享了一道扑克牌诈金花的题目,要求用Python实现,题目如下:
自己写一个程序,实现发牌、比大小判断输赢。
游戏规则:
一付扑克牌,去掉大小王,每个玩家发3张牌,最后比大小,看谁赢。
有以下几种牌:
豹子:三张一样的牌,如3张6.
顺金:又称同花顺,即3张同样花色的顺子, 如红桃 5、6、7
顺子:又称拖拉机,花色不同,但是顺子,如红桃5、方片6、黑桃7,组成的顺子
对子:2张牌一样
单张:单张最大的是A
这几种牌的大小顺序为, 豹子>顺金>顺子>对子>单张
一、思路
针对这个问题,首先需要构造一副扑克牌,根据扑克牌的属性特征,进行不断的拆解,然后构造玩家用户,这里经常会用到字典和列表来存储信息,屡试不爽。
二、解决方案
针对该问题,粉丝【^-^】给出了解决方法,直接上代码如下:
# -*- coding: utf-8 -*- import random puke = [] # 存储扑克牌 num_list = ['2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K', 'A'] hua_list = ['梅花', '红桃', '黑桃', '方块'] sort_dic = {'2': 0, '3': 1, '4': 2, '5': 3, '6': 4, '7': 5, '8': 6, '9': 7, '10': 8, 'J': 9, 'Q': 10, 'K': 11, 'A': 12, '对子': 15, '顺子': 30, '顺金': 60, '豹子': 100} count_new_list = [] # 存储玩家分数和排序后排名 count_dic = {} # 存储玩家分数 # 准备52张扑克 for hua in hua_list: for num in num_list: a = hua + num puke.append(a) player_dic = {'玩家1': [], '玩家2': [], '玩家3': [], '玩家4': [], '玩家5': []} # 随机给五个玩家发牌 # print(len(puke)) for key, value in player_dic.items(): for i in range(3): plate = random.sample(puke, 3) player_dic[key] = plate for i in plate: puke.remove(i) print(player_dic) # 获取玩家的牌型 def paixing(list1): num = [] huase = [] for i in list1: a = i[2:] b = i[:2] num.append(a) huase.append(b) return num, huase # sort_dic = {'2': 0, '3': 1, '4': 2, '5': 3, '6': 4} # 对数字的牌型进行排序 def sort(num): new_num = [] sort_list2 = [] list1 = [] for i in num: new_num.append(sort_dic[i]) new_num = sorted(new_num) # 排序后是[2, 4, 7] for new in new_num: sort_list2.append([k for k, v in sort_dic.items() if v == new]) for m in sort_list2: for n in m: list1.append(n) return list1 # 对玩家的牌形统计分数 def count(num, huase): a = 0 base_count = sort_dic[num[0]] + sort_dic[num[1]] + sort_dic[num[2]] if num[0] == num[1] and num[1] == num[2]: paixing = '豹子' a = base_count + sort_dic[paixing] elif (sort_dic[num[0]] + 1 == sort_dic[num[1]] and sort_dic[num[2]] - 1 == sort_dic[num[1]]) and (huase[0] == huase[ 1] and huase[1] == huase[2]): paixing = '顺金' a = base_count + sort_dic[paixing] elif (sort_dic[num[0]] + 1 == sort_dic[num[1]]) and (sort_dic[num[2]] - 1 == sort_dic[num[1]]) and ( huase[0] != huase[ 1] or huase[1] != huase[2]): paixing = '顺子' a = base_count + sort_dic[paixing] elif (num[0] == num[1] and num[1] != num[2]) or (num[1] == num[2] and num[0] != num[1]) or ( num[0] == num[2] and num[1] != num[0]): paixing = '对子' a = base_count + sort_dic[paixing] else: a = base_count return a # 对存储玩家分数的字典进行排序 def compare(count_dic): d = list(zip(count_dic.values(), count_dic.keys())) return sorted(d, reverse=True) for key, value in player_dic.items(): num, huase = paixing(value) num = sort(num) count1 = count(num, huase) count_dic[key] = count1 print(key + "的牌为:" + str(value)) count_new_list = compare(count_dic) # print(count_new_list) print('最终排名:' + "\t" + count_new_list[0][1] + "第一名" + "\t" + count_new_list[1][1] + "第二名" + "\t" + count_new_list[2][ 1] + "第三名" + "\t" + count_new_list[3][1] + "第四名" + "\t" + count_new_list[4][1] + "第五名")
代码看上去确实挺多的,超过了100行,需要花点时间去读,不过涉及的知识点并不复杂,基本上有点Python基础,也可以理解。代码运行之后,可以看到效果如下:
不过后来我在读取这份代码的时候,发现中间有个地方写的着实有些冗余,稍微修改下,代码方面简洁一些,一些函数和变量命名加了一些对应的现实意义的单词,可读性强了一丢丢,代码如下:
# -*- coding: utf-8 -*- import random puke = [] # 存储扑克牌 num_list = ['2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K', 'A'] hua_list = ['梅花', '红桃', '黑桃', '方块'] sort_dic = {'2': 0, '3': 1, '4': 2, '5': 3, '6': 4, '7': 5, '8': 6, '9': 7, '10': 8, 'J': 9, 'Q': 10, 'K': 11, 'A': 12, '对子': 15, '顺子': 30, '顺金': 60, '豹子': 100} count_new_list = [] # 存储玩家分数和排序后排名 count_dic = {} # 存储玩家分数 # 准备52张扑克 for hua in hua_list: for num in num_list: a = hua + num puke.append(a) player_dic = {'玩家1': [], '玩家2': [], '玩家3': [], '玩家4': [], '玩家5': []} # 随机给五个玩家发牌 print(len(puke)) for key, value in player_dic.items(): for i in range(3): plate = random.sample(puke, 3) player_dic[key] = plate for i in plate: puke.remove(i) print(player_dic) # 获取玩家的牌型 def paixing(list1): num = [] huase = [] for data in list1: huase_type = data[:2] pai_number = data[2:] num.append(pai_number) huase.append(huase_type) return num, huase # 对玩家的牌形统计分数 def get_score(num, huase): base_count = sort_dic[num[0]] + sort_dic[num[1]] + sort_dic[num[2]] if num[0] == num[1] and num[1] == num[2]: paixing = '豹子' score = base_count + sort_dic[paixing] elif (sort_dic[num[0]] + 1 == sort_dic[num[1]] and sort_dic[num[2]] - 1 == sort_dic[num[1]]) and (huase[0] == huase[ 1] and huase[1] == huase[2]): paixing = '顺金' score = base_count + sort_dic[paixing] elif (sort_dic[num[0]] + 1 == sort_dic[num[1]]) and (sort_dic[num[2]] - 1 == sort_dic[num[1]]) and ( huase[0] != huase[ 1] or huase[1] != huase[2]): paixing = '顺子' score = base_count + sort_dic[paixing] elif (num[0] == num[1] and num[1] != num[2]) or (num[1] == num[2] and num[0] != num[1]) or ( num[0] == num[2] and num[1] != num[0]): paixing = '对子' score = base_count + sort_dic[paixing] else: score = base_count return score if __name__ == '__main__': for key, value in player_dic.items(): num, huase = paixing(value) # 对数字的牌型进行排序 num = sorted(num) score = get_score(num, huase) count_dic[key] = score print(key + "的牌为:" + str(value)) # 对存储玩家分数的字典进行排序 count_new_list = sorted(zip(count_dic.values(), count_dic.keys()), reverse=True) print("最终排名:") for i in range(len(count_new_list)): print(count_new_list[i][1] + '\t', end='')
三、总结
我是Python进阶者。本文实际生活中的诈金花游戏,基于Python编程,使用Python基础知识中的列表、字典、函数等,实现了在线诈金花的过程。
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