TensorFlow的reshape操作 tf.reshape TensorFlow的reshape操作 tf.reshape的实现
Ai_践行者 人气:0初学tensorflow,如果写的不对的,请更正,谢谢!
tf.reshape(tensor, shape, name=None)
函数的作用是将tensor变换为参数shape的形式。
其中shape为一个列表形式,特殊的一点是列表中可以存在-1。-1代表的含义是不用我们自己指定这一维的大小,函数会自动计算,但列表中只能存在一个-1。(当然如果存在多个-1,就是一个存在多解的方程了)
好了我想说的重点还有一个就是根据shape如何变换矩阵。其实简单的想就是,
reshape(t, shape) => reshape(t, [-1]) => reshape(t, shape)
首先将矩阵t变为一维矩阵,然后再对矩阵的形式更改就可以了。
官方的例子:
# tensor 't' is [1, 2, 3, 4, 5, 6, 7, 8, 9] # tensor 't' has shape [9] reshape(t, [3, 3]) ==> [[1, 2, 3], [4, 5, 6], [7, 8, 9]] # tensor 't' is [[[1, 1], [2, 2]], # [[3, 3], [4, 4]]] # tensor 't' has shape [2, 2, 2] reshape(t, [2, 4]) ==> [[1, 1, 2, 2], [3, 3, 4, 4]] # tensor 't' is [[[1, 1, 1], # [2, 2, 2]], # [[3, 3, 3], # [4, 4, 4]], # [[5, 5, 5], # [6, 6, 6]]] # tensor 't' has shape [3, 2, 3] # pass '[-1]' to flatten 't' reshape(t, [-1]) ==> [1, 1, 1, 2, 2, 2, 3, 3, 3, 4, 4, 4, 5, 5, 5, 6, 6, 6] # -1 can also be used to infer the shape # -1 is inferred to be 9: reshape(t, [2, -1]) ==> [[1, 1, 1, 2, 2, 2, 3, 3, 3], [4, 4, 4, 5, 5, 5, 6, 6, 6]] # -1 is inferred to be 2: reshape(t, [-1, 9]) ==> [[1, 1, 1, 2, 2, 2, 3, 3, 3], [4, 4, 4, 5, 5, 5, 6, 6, 6]] # -1 is inferred to be 3: reshape(t, [ 2, -1, 3]) ==> [[[1, 1, 1], [2, 2, 2], [3, 3, 3]], [[4, 4, 4], [5, 5, 5], [6, 6, 6]]] # tensor 't' is [7] # shape `[]` reshapes to a scalar reshape(t, []) ==> 7
在举几个例子或许就清楚了,有一个数组z,它的shape属性是(4, 4)
z = np.array([[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]]) z.shape (4, 4)
z.reshape(-1)
z.reshape(-1) array([ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16])
z.reshape(-1, 1)
也就是说,先前我们不知道z的shape属性是多少,但是想让z变成只有一列,行数不知道多少,通过`z.reshape(-1,1)`,Numpy自动计算出有12行,新的数组shape属性为(16, 1),与原来的(4, 4)配套。
z.reshape(-1,1) array([[ 1], [ 2], [ 3], [ 4], [ 5], [ 6], [ 7], [ 8], [ 9], [10], [11], [12], [13], [14], [15], [16]])
z.reshape(-1, 2)
newshape等于-1,列数等于2,行数未知,reshape后的shape等于(8, 2)
z.reshape(-1, 2) array([[ 1, 2], [ 3, 4], [ 5, 6], [ 7, 8], [ 9, 10], [11, 12], [13, 14], [15, 16]])
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