Python3查找列表中重复元素的个数方法 Python3查找列表中重复元素的个数的3种方法详解
猪笨是念来过倒 人气:0方法一:
mylist = [1,2,2,2,2,3,3,3,4,4,4,4] myset = set(mylist) for item in myset: print("the %d has found %d" %(item,mylist.count(item)))
the 1 has found 1
the 2 has found 4
the 3 has found 3
the 4 has found 4
方法二:
from collections import Counter Counter([1,2,2,2,2,3,3,3,4,4,4,4]) Counter({2: 4, 4: 4, 3: 3, 1: 1})
方法三:
List=[1,2,2,2,2,3,3,3,4,4,4,4] a = {} for i in List: if List.count(i)>1: a[i] = List.count(i)
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