python打印单链表 python实现从尾到头打印单链表操作示例
franklin_yuan 人气:2本文实例讲述了python实现从尾到头打印单链表操作。分享给大家供大家参考，具体如下：
# coding=utf-8
class SingleNode:
def __init__(self, item):
self.item = item
self.next = None
class SingleLinkedList:
"""
is_empty() 链表是否为空
print_end_to_head() 从尾到头打印单链表
append(item) 链表尾部添加元素
"""
def __init__(self):
self._head = None
def is_empty(self):
return self._head is None
def append(self, item):
if self.is_empty():
self._head = item
else:
cur = self._head
while cur.next:
cur = cur.next
cur.next = item
def print_end_to_head(self):
"""从尾到头打印单链表"""
if self.is_empty():
print(None)
return
tmp = []
cur = self._head
while cur:
tmp.insert(0, cur)
cur = cur.next
for i in tmp:
print(i.item)
if __name__ == '__main__':
sl = SingleLinkedList()
sl.append(SingleNode(1))
sl.append(SingleNode(2))
sl.append(SingleNode(3))
sl.append(SingleNode(4))
sl.print_end_to_head()
运行结果：
4
3
2
1
PS：对象obj的打印，可使用如下语句实现：
print '\n'.join(['%s:%s' % item for item in obj.__dict__.items()])
希望本文所述对大家Python程序设计有所帮助。
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