PyQt5 QTableWidget 弹出菜单 PyQt5中QTableWidget怎样弹出菜单的代码实例

from PyQt5 import QtCore
from PyQt5.QtCore import QSize, Qt
from PyQt5.QtGui import *
from PyQt5.QtWidgets import *

'''
如何弹出菜单
如何在满足条件的情况下弹出菜单
'''
class TableWidgetContextMenu(QWidget):
  def __init__(self):
    super(TableWidgetContextMenu, self).__init__()
    self.initUI()

  def initUI(self):
    self.setWindowTitle("在表格中显示上下文菜单")
    self.resize(500, 300)
    layout = QHBoxLayout()

    self.tableWidget = QTableWidget()
    self.tableWidget.setRowCount(5)
    self.tableWidget.setColumnCount(3)

    layout.addWidget(self.tableWidget)

    self.tableWidget.setHorizontalHeaderLabels(['姓名', '性别', '年龄'])

    # 第一行
    Item1 = QTableWidgetItem("老王")
    self.tableWidget.setItem(0, 0, Item1)

    Item2 = QTableWidgetItem("男")
    self.tableWidget.setItem(0, 1, Item2)

    Item3 = QTableWidgetItem("30")
    self.tableWidget.setItem(0, 2, Item3)

    # 第二行
    Item1 = QTableWidgetItem("小王")
    self.tableWidget.setItem(1, 0, Item1)

    Item2 = QTableWidgetItem("男")
    self.tableWidget.setItem(1, 1, Item2)

    Item3 = QTableWidgetItem("28")
    self.tableWidget.setItem(1, 2, Item3)

    # 第三行
    Item1 = QTableWidgetItem("小红")
    self.tableWidget.setItem(2, 0, Item1)

    Item2 = QTableWidgetItem("女")
    self.tableWidget.setItem(2, 1, Item2)

    Item3 = QTableWidgetItem("18")
    self.tableWidget.setItem(2, 2, Item3)

    # 允许弹出菜单
    self.tableWidget.setContextMenuPolicy(Qt.CustomContextMenu)

    # 将信号请求连接到槽（单击鼠标右键，就调用方法）
    self.tableWidget.customContextMenuRequested.connect(self.generateMenu)

    self.setLayout(layout)

  # pos为点击的位置
  def generateMenu(self, pos):
    print(pos)
    # 得到索引
    for i in self.tableWidget.selectionModel().selection().indexes():
      rowNum = i.row()

    # 如果选择的行索引小于1，弹出上下文菜单
    if rowNum < 3:
      menu = QMenu()
      item1 = menu.addAction("菜单1")
      item2 = menu.addAction("菜单2")
      item3 = menu.addAction("菜单3")
      # 使菜单在正常位置显示
      screenPos = self.tableWidget.mapToGlobal(pos)

      # 单击一个菜单项就返回，使之被阻塞
      action = menu.exec(screenPos)
      if action == item1:
        print('选择菜单1', self.tableWidget.item(rowNum, 0).text())
      if action == item2:
        print('选择菜单2', self.tableWidget.item(rowNum, 0).text())
      if action == item3:
        print('选择菜单3', self.tableWidget.item(rowNum, 0).text())
      else:
        return



if __name__ == "__main__":
  app = QApplication(sys.argv)
  main = TableWidgetContextMenu()
  main.show()
  sys.exit(app.exec_())