python井字棋游戏 python实现简单井字棋小游戏
蒟蒻熊 人气:0用python实现的一个井字棋游戏,供大家参考,具体内容如下
#Tic-Tac-Toe 井字棋游戏 #全局常量 X="X" O="O" EMPTY=" " #询问是否继续 def ask_yes_no(question): response=None; while response not in("y","n"): response=input(question).lower() return response #输入位置数字 def ask_number(question ,low,high): response=None while response not in range(low,high): response=int(input(question)) return response #询问谁先走,先走方为X,后走方为O #函数返回计算机方,玩家的角色代号 def pieces(): go_first=ask_yes_no("玩家你是否先走(y/n):") if go_first=="y": print("\n玩家你先走.") human=X computer=O else: print("\n计算机先走.") computer=X human=O return computer,human #产生新的棋盘 def new_board(): board=[] for square in range(9): board.append(EMPTY) return board #显示棋盘 def display_board(board): board2=board[:] for i in range(len(board)): if board[i]==EMPTY: board2[i]=i print("\t",board2[0],"|",board2[1],"|",board2[2]) print("\t","----------") print("\t",board2[3],"|",board2[4],"|",board2[5]) print("\t", "----------") print("\t",board2[6],"|",board2[7],"|",board2[8],"\n") #产生可以合法走棋位置序列(也就是还未下过子位置) def legal_moves(board): moves=[] for square in range(9): if board[square]==EMPTY: moves.append(square) return moves #判断输赢 def winner(board): # 所有赢得可能情况,例如(0,1,2)就是第一行,(0,4,8,),(2,4,6)就是对角线 WAYS_TO_WIN=((0,1,2,),(3,4,5),(6,7,8),(0,3,6),(1,4,7),(2,5,8),(0,4,8),(2,4,6)) for row in WAYS_TO_WIN: if board[row[0]]==board[row[1]]==board[row[2]]!=EMPTY: winner=board[row[0]] return winner #棋盘没有空位置 if EMPTY not in board: return "TIE" return False #人走棋 def human_move (board,human): legal =legal_moves(board) move =None while move not in legal: move=ask_number("你走那个位置?(0-8):",0,9) if move not in legal: print("\n此位置已经落过子了") #print("Fine...") return move #计算机走棋 def computer_move(board,computer ,human): board=board[:] #按优劣顺序排序的下棋走子 BEST_MOVES=(4,0,2,6,8,1,3,5,7) #最佳下棋位置顺序表 #如果计算机能赢,就走那个位置 for move in legal_moves(board): board[move]=computer if winner(board)==computer: print("计算机下棋位置...",move) return move #取消走棋方案 board[move]=EMPTY #如果玩家能赢就堵住那个位置 for move in legal_moves(board): board[move]=human if winner(board)==human: print("计算机下棋位置...",move) return move #取消走棋方案 board[move]=EMPTY #如果不是上面情况,也就是这一轮赢不了 #则是从最佳下棋位置表中挑出第一个合法位置 for move in BEST_MOVES: if move in legal_moves(board): print("计算机下棋位置....",move) return move #转换角色 def next_turn(turn): if turn ==X: return O else: return X #主函数 def main(): computer,human=pieces() turn =X board=new_board() display_board(board) while not winner(board): if turn ==human: move=human_move(board,human) board[move]=human else: move=computer_move(board,computer,human) board[move]=computer display_board(board) turn=next_turn(turn) #转换角色 #游戏结束输出输赢或和棋信息 the_winner=winner(board) if the_winner==computer: print("计算机赢!\n") elif the_winner==human: print("玩家赢!\n") elif the_winner=="TIE": print("平局,游戏结束\n") main() input("按任意键退出游戏")
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