python利用7z批量解压rar的实现
人气:0一开始我使用了rarfile这个库,奈何对于含有密码的压缩包支持不好,在linux上不抛出异常;之后有又尝试了unrar。。比rarfile还费劲。。
所以用了调用系统命令的方法,用7z来解压
通过apt可以安装上7z-full和7z的rar插件
有一个地方要注意 -o 和-p与后面的目录、密码之间没有空格!!
同样可以用这个代码暴力破解压缩包密码
# coding:utf-8 import os import zipfile import traceback import time import shutil import sys,getopt succeedpath="" unsucceedpath="" psds={"2018","123456"} opts,args=getopt.getopt(sys.argv[1:],"p:") path=args[0] for psd in args[1:]: psds.add(psd) #for op,value in opts: # if op in ("-p","--password"): # psds.add(value) def mkdirs(dirpath): global succeedpath,unsucceedpath succeedpath=os.path.join(dirpath,"0.succeed") unsucceedpath=os.path.join(dirpath,"0.unsucceed") if(not os.path.exists(succeedpath)): os.makedirs(succeedpath) if(not os.path.exists(unsucceedpath)): os.makedirs(unsucceedpath) def extractdir(path): for filename in os.listdir(path): filepath=os.path.join(path,filename) if(os.path.isfile(filepath)): extractfile(filepath) def extractfile(path): (dirpath,filen)=os.path.split(path) print("解压"+filen+" ing...") try: if(filen.endswith(".rar") or filen.endswith(".zip")): path=os.path.abspath(path) dirpath=os.path.abspath(dirpath) cmd="7z x "+path+" -o"+dirpath+" -y "+" -p" state=False if(os.system(cmd)==0): state=True else: for psd in psds: cmdp="7z x "+path+" -p"+psd+" -y "+" -o"+dirpath if(os.system(cmdp)==0): state=True break else: return if (state): shutil.move(path,succeedpath) else: shutil.move(path,unsucceedpath) with open(os.path.join(dirpath,"errorinfo.txt"),"a+") as errorinfo: errorinfo.write("time:"+str(time.time())+"\n") errorinfo.write("解压出错!\n可能是密码错误!\n") except : with open(os.path.join(dirpath,"errorinfo.txt"),"a+") as errorinfo: errorinfo.write("time:"+str(time.time())+"\n") errorinfo.write("解压出错!\n") traceback.print_exc(file=errorinfo) shutil.move(path,unsucceedpath) if(os.path.isdir(path)): dirpath=path mkdirs(dirpath) extractdir(dirpath) elif(os.path.isfile(path)): filepath=path (dirpath,filename)=os.path.split(path) mkdirs(dirpath) extractfile(path) else: print("输入错误!请重新输入!")
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