layui form表单提交之后重新加载数据表格的方法

<p style="text-align: center"><img src="https://img.qb5200.com/download-x/20210402/99763.jpg" alt="" /></p>

<div class="layui-row">
 <form class="layui-form layui-col-md12 x-so" id="zq_search">
  菜单：<input id="name" type="text" name="name" placeholder="请输入菜单" autocomplete="off" class="layui-input">
  <button id="search" class="layui-btn" lay-submit="" lay-filter="search"><i class="layui-icon"></i></button>
 </form>
</div>

$(function () {
 //注意：这里是数据表格的加载数据，必须写
 layui.use(['table', 'layer', 'form', 'laypage', 'laydate'], function () {
 var table = layui.table //表格
  ,layer = layui.layer //弹层
  ,form = layui.form //form表单
  // ..................
 
 //监听提交 lay-filter="search"
 form.on('submit(search)', function(data){
  var formData = data.field;
  var name = formData.name,
  url=formData.url,
  icon=formData.icon,
  parent_id=formData.parent_id;
  //执行重载
  table.reload('tableReload', {
  page: {
   curr: 1 //重新从第 1 页开始
  }
  , where: {//这里传参 向后台
   name: name
   //可传多个参数到后台... ，分隔
  }
  , url: '/menu/page'//后台做模糊搜索接口路径
  , method: 'post'
  });
  return false;//false：阻止表单跳转 true：表单跳转
 });
 
 });
});