Python计算两个矩形重合面积代码实例
人气:0这篇文章主要介绍了Python 实现两个矩形重合面积代码实例,文中通过示例代码介绍的非常详细,对大家的学习或者工作具有一定的参考学习价值,需要的朋友可以参考下
代码如下
计算两个矩形的重合面积
import math x1, y1, x2, y2 = input().split(" ") x1, y1, x2, y2=int(x1), int(y1), int(x2), int(y2) # print(x1, y1, x2, y2) x1,x2 = min(x1,x2),max(x1,x2) y1,y2= min(y1,y2),max(y1,y2) # print(x1, y1, x2, y2) x3, y3, x4, y4 = input().split(" ") x3, y3, x4, y4 = int(x3), int(y3), int(x4), int(y4) x3,x4 = min(x3,x4),max(x3,x4) y3,y4 = min(y3,y4),max(y3,y4) # print(x3, y3, x4, y4) if (x2<=x3 or x4<=x1) and (y2 <= y3 or y4<=y1): print(0) else: lens = min(x2, x4) - max(x1, x3) wide = min(y2, y4) - max(y1, y3) print(lens*wide)
字符串重叠输出
import string in_str = input() nums = string.digits a = "" strs = "" num = "" for i in range(len(in_str)): if in_str[i] not in nums: a = a+in_str[i] else: if i == len(in_str)-1 or (in_str[i+1] not in nums): num = int(num + in_str[i]) strs = strs + a*num a="" num="" else: num = num + in_str[i] print(strs)
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