详解python路径拼接os.path.join()函数的用法
人气:0os.path.join()函数:连接两个或更多的路径名组件
1.如果各组件名首字母不包含'/',则函数会自动加上
demo1
import os Path1 = 'home' Path2 = 'develop' Path3 = 'code' Path10 = Path1 + Path2 + Path3 Path20 = os.path.join(Path1,Path2,Path3) print ('Path10 = ',Path10) print ('Path20 = ',Path20)
输出:
Path10 = homedevelopcode
Path20 = home\develop\code
2.如果有一个组件是一个绝对路径,则在它之前的所有组件均会被舍弃
demo2
import os Path1 = '/home' Path2 = 'develop' Path3 = 'code' Path10 = Path1 + Path2 + Path3 Path20 = os.path.join(Path1, Path2, Path3) Path30 = os.path.join(Path2, Path1, Path3) print('Path10 = ',Path10) print('Path20 = ',Path20) print('Path30 = ',Path30)
输出:
Path10 = /homedevelopcode
Path20 = /home\develop\code
Path30 = /home\code
3.如果最后一个组件为空,则生成的路径以一个'/'分隔符结尾
demo3
import os Path1 = 'home' Path2 = 'develop' Path3 = '' Path10 = Path1 + Path2 + Path3 Path20 = os.path.join(Path1, Path2, Path3) Path30 = os.path.join(Path2, Path1, Path3) print('Path10 = ',Path10) print('Path20 = ',Path20)
输出:
Path10 = homedevelop
Path20 = home\develop\
总结
以上所述是小编给大家介绍的python路径拼接os.path.join()函数的用法,希望对大家有所帮助,如果大家有任何疑问请给我留言,小编会及时回复大家的。在此也非常感谢大家对网站的支持!
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