python不使用for计算两组、多个矩形两两间的iou方式

def calc_iou(bbox1, bbox2):
 if not isinstance(bbox1, np.ndarray):
  bbox1 = np.array(bbox1)
 if not isinstance(bbox2, np.ndarray):
  bbox2 = np.array(bbox2)
 xmin1, ymin1, xmax1, ymax1, = np.split(bbox1, 4, axis=-1)
 xmin2, ymin2, xmax2, ymax2, = np.split(bbox2, 4, axis=-1)
 
 area1 = (xmax1 - xmin1) * (ymax1 - ymin1)
 area2 = (xmax2 - xmin2) * (ymax2 - ymin2)
 
 ymin = np.maximum(ymin1, np.squeeze(ymin2, axis=-1))
 xmin = np.maximum(xmin1, np.squeeze(xmin2, axis=-1))
 ymax = np.minimum(ymax1, np.squeeze(ymax2, axis=-1))
 xmax = np.minimum(xmax1, np.squeeze(xmax2, axis=-1))
 
 h = np.maximum(ymax - ymin, 0)
 w = np.maximum(xmax - xmin, 0)
 intersect = h * w
 
 union = area1 + np.squeeze(area2, axis=-1) - intersect
 return intersect / union

def delete_bbox(bbox1, bbox2, roi_bbox1, roi_bbox2, class1, class2, idx1, idx2, iou_value):
 idx = np.where(iou_value > 0.4)
 left_idx = idx[0]
 right_idx = idx[1]
 left = roi_bbox1[left_idx]
 right = roi_bbox2[right_idx]
 xmin1, ymin1, xmax1, ymax1, = np.split(left, 4, axis=-1)
 xmin2, ymin2, xmax2, ymax2, = np.split(right, 4, axis=-1)
 left_area = (xmax1 - xmin1) * (ymax1 - ymin1)
 right_area = (xmax2 - xmin2) * (ymax2 - ymin2)
 left_idx = left_idx[np.squeeze(left_area < right_area, axis=-1)]#小的被删
 right_idx = right_idx[np.squeeze(left_area > right_area, axis=-1)]
 
 bbox1 = np.delete(bbox1, idx1[left_idx], 0)
 class1 = np.delete(class1, idx1[left_idx])
 bbox2 = np.delete(bbox2, idx2[right_idx], 0)
 class2 = np.delete(class2, idx2[right_idx])
 
 return bbox1, bbox2, class1, class2

ymin = np.maximum(ymin1, np.squeeze(ymin2, axis=-1))

xmin = np.maximum(xmin1, np.squeeze(xmin2, axis=-1))

ymax = np.minimum(ymax1, np.squeeze(ymax2, axis=-1))

xmax = np.minimum(xmax1, np.squeeze(xmax2, axis=-1))

h = np.maximum(ymax - ymin, 0)

w = np.maximum(xmax - xmin, 0)

intersect = h * w