python实现人民币转大写人民币 python2.x实现人民币转大写人民币

# -*- coding: utf-8 -*-
def changenum( change_number ):
 format_num = ["零","壹","贰","叁","肆","伍","陆","柒","捌","玖"]
 format_name = ["分", "角", "元",
    "拾","百","千","万",
    "拾","百","千","亿",
    "拾","百","千","万",
    "拾","百","千","兆"]

 if type( change_number ) == str:
  if '.' in change_number:
   try: change_number = float( change_number )
   except: raise ValueError, '%s can\'t change'%change_number
  else:
   try: change_number = int( change_number )
   except: raise ValueError, '%s can\'t change'%change_number

 if type( change_number ) == float:
  real_numbers = []
  for i in range( len( format_name ) - 3, -3, -1 ):
   if change_number >= 10 ** i or i < 1:
    real_numbers.append( int( round( change_number/( 10**i ), 2)%10 ) )

 elif isinstance( change_number, (int, long) ):
  real_numbers = [ int( i ) for i in str( change_number ) + '00' ]

 else:
  raise ValueError, '%s can\'t change'%change_number

 zflag = 0      
 start = len(real_numbers) - 3
 change_words = []
 for i in range(start, -3, -1): 
  if 0 <> real_numbers[start-i] or len(change_words) == 0:
   if zflag:
    change_words.append(format_num[0])
    zflag = 0
   change_words.append( format_num[ real_numbers[ start - i ] ] )
   change_words.append(format_name [i+2])

  elif 0 == i or (0 == i%4 and zflag < 3): 
   change_words.append(format_name [i+2])
   zflag = 0
  else:
   zflag += 1

 if change_words[-1] not in (format_name[0], format_name[1]):
  change_words.append("整")

 return ''.join(change_words)
#测试
# print changenum(865324.98)
#查看输出的结果是否正确