python dataframe向下向上填充,fillna和ffill python dataframe向下向上填充,fillna和ffill的方法
chenKFKevin 人气:3首先新建一个dataframe:
In[8]: df = pd.DataFrame({'name':list('ABCDA'),'house':[1,1,2,3,3],'date':['2010-01-01','2010-06-09','2011-12-03','2011-04-05','2012-03-23']}) In[9]: df Out[9]: date house name 0 2010-01-01 1 A 1 2010-06-09 1 B 2 2011-12-03 2 C 3 2011-04-05 3 D 4 2012-03-23 3 A
将date列改为时间类型:
In[12]: df.date = pd.to_datetime(df.date)
数据的含义是这样的,我们有ABCD四个人的数据,已知A在2010-01-01的时候,名下有1套房,B在2010-06-09的时候,名下有1套房,C在2011-12-03的时候,有2套房,D在2011-04-05的时候有3套房,A在2012-02-23的时候,数据更新了,有两套房。
要求在有姓名和时间的情况下,能给出其名下有几套房:
比如A在2010-01-01与2012-03-23期间任意一天,都应该是1套房,在2012-03-23之后,都是3套房。
我们使用pandas的fillna方法,选择ffill。
首先我们获得一个2010-01-01到2017-12-01的dataframe
In[14]: time_range = pd.DataFrame( pd.date_range('2010-01-01','2017-12-01',freq='D'), columns=['date']).set_index("date") In[15]: time_range Out[15]: Empty DataFrame Columns: [] Index: [2010-01-01 00:00:00, 2010-01-02 00:00:00, 2010-01-03 00:00:00, 2010-01-04 00:00:00, 2010-01-05 00:00:00, 2010-01-06 00:00:00, 2010-01-07 00:00:00, 2010-01-08 00:00:00, 2010-01-09 00:00:00, 2010-01-10 00:00:00, 2010-01-11 00:00:00, 2010-01-12 00:00:00, 2010-01-13 00:00:00, 2010-01-14 00:00:00, 2010-01-15 00:00:00, 2010-01-16 00:00:00, 2010-01-17 00:00:00, 2010-01-18 00:00:00, 2010-01-19 00:00:00, 2010-01-20 00:00:00, 2010-01-21 00:00:00, 2010-01-22 00:00:00, 2010-01-23 00:00:00, 2010-01-24 00:00:00, 2010-01-25 00:00:00, 2010-01-26 00:00:00, 2010-01-27 00:00:00, 2010-01-28 00:00:00, 2010-01-29 00:00:00, 2010-01-30 00:00:00, 2010-01-31 00:00:00, 2010-02-01 00:00:00, 2010-02-02 00:00:00, 2010-02-03 00:00:00, 2010-02-04 00:00:00, 2010-02-05 00:00:00, 2010-02-06 00:00:00, 2010-02-07 00:00:00, 2010-02-08 00:00:00, 2010-02-09 00:00:00, 2010-02-10 00:00:00, 2010-02-11 00:00:00, 2010-02-12 00:00:00, 2010-02-13 00:00:00, 2010-02-14 00:00:00, 2010-02-15 00:00:00, 2010-02-16 00:00:00, 2010-02-17 00:00:00, 2010-02-18 00:00:00, 2010-02-19 00:00:00, 2010-02-20 00:00:00, 2010-02-21 00:00:00, 2010-02-22 00:00:00, 2010-02-23 00:00:00, 2010-02-24 00:00:00, 2010-02-25 00:00:00, 2010-02-26 00:00:00, 2010-02-27 00:00:00, 2010-02-28 00:00:00, 2010-03-01 00:00:00, 2010-03-02 00:00:00, 2010-03-03 00:00:00, 2010-03-04 00:00:00, 2010-03-05 00:00:00, 2010-03-06 00:00:00, 2010-03-07 00:00:00, 2010-03-08 00:00:00, 2010-03-09 00:00:00, 2010-03-10 00:00:00, 2010-03-11 00:00:00, 2010-03-12 00:00:00, 2010-03-13 00:00:00, 2010-03-14 00:00:00, 2010-03-15 00:00:00, 2010-03-16 00:00:00, 2010-03-17 00:00:00, 2010-03-18 00:00:00, 2010-03-19 00:00:00, 2010-03-20 00:00:00, 2010-03-21 00:00:00, 2010-03-22 00:00:00, 2010-03-23 00:00:00, 2010-03-24 00:00:00, 2010-03-25 00:00:00, 2010-03-26 00:00:00, 2010-03-27 00:00:00, 2010-03-28 00:00:00, 2010-03-29 00:00:00, 2010-03-30 00:00:00, 2010-03-31 00:00:00, 2010-04-01 00:00:00, 2010-04-02 00:00:00, 2010-04-03 00:00:00, 2010-04-04 00:00:00, 2010-04-05 00:00:00, 2010-04-06 00:00:00, 2010-04-07 00:00:00, 2010-04-08 00:00:00, 2010-04-09 00:00:00, 2010-04-10 00:00:00, ...] [2892 rows x 0 columns]
然后用上上篇博客中提到的pivot_table将原本的df转变之后,与time_range进行merger操作。
In[16]: df = pd.pivot_table(df, columns='name', index='date') In[17]: df Out[17]: house name A B C D date 2010-01-01 1.0 NaN NaN NaN 2010-06-09 NaN 1.0 NaN NaN 2011-04-05 NaN NaN NaN 3.0 2011-12-03 NaN NaN 2.0 NaN 2012-03-23 3.0 NaN NaN NaN In[18]: df = df.merge(time_range,how="right", left_index=True, right_index=True)
然后再进行向下填充操作:
In[20]: df = df.fillna(method='ffill')
最后:
df = df.stack().reset_index()
结果太长,这里就不粘贴了。如果想向上填充,可选择method = 'bfill‘
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