python解析json串与正则匹配对比 python解析json串与正则匹配对比方法

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#!/usr/bin/env python
#coding:utf-8

import json
import sys
import collections
import time

def t1():
 start = time.clock()
 for line in sys.stdin:
  try:
   line = line.strip()
   decoded = json.loads(line)
   device_id = decoded["device_id"]
   print device_id
  except Exception,ex:
   pass

 end = time.clock()
 print "The cost time is: %f" %(end - start)

t1()

#!/usr/bin/env python

import re
import sys
import time

def t1():
 start = time.clock()
 count = 0
 for line in sys.stdin:
  line = line.strip()
  pattern = re.compile("(?:\"device_id\":\")([^\"]+)")
  search = pattern.search(line)
  if search:
   count += 1
   #print search.groups()[0]
 end = time.clock()
 print "The count is: %d" %(count)
 print "The cost time is: %f" %(end - start)

t1()

re.compile("(?:\"device_id\":\")([^\"]+)")