Python3判断环形链表算法 Python3实现的判断环形链表算法示例
zhenghaitian 人气:0本文实例讲述了Python3实现的判断环形链表算法。分享给大家供大家参考,具体如下:
给定一个链表,判断链表中是否有环。
方案一:快慢指针遍历,若出现相等的情况,说明有环
# Definition for singly-linked list. # class ListNode(object): # def __init__(self, x): # self.val = x # self.next = None class Solution(object): def hasCycle(self, head): """ :type head: ListNode :rtype: bool """ slow = fast = head while fast and fast.next: slow = slow.next fast = fast.next.next if fast == slow: return True return False
方案二:遍历链表,寻找.next=head的元素。 但超出时间限制
# Definition for singly-linked list. # class ListNode(object): # def __init__(self, x): # self.val = x # self.next = None class Solution(object): def hasCycle(self, head): """ :type head: ListNode :rtype: bool """ if not head: return False cur = head.next while cur: if cur.next == head: return True cur = cur.next return False
希望本文所述对大家Python程序设计有所帮助。
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