亲宝软件园·资讯

展开

C语言直角坐标转换为极坐标 C语言实现直角坐标转换为极坐标的方法

e421083458 人气:0
想了解C语言实现直角坐标转换为极坐标的方法的相关内容吗,e421083458在本文为您仔细讲解C语言直角坐标转换为极坐标的相关知识和一些Code实例,欢迎阅读和指正,我们先划重点:C语言,直角坐标,转换,极坐标,下面大家一起来学习吧。

本文实例讲述了C语言实现直角坐标转换为极坐标的方法。分享给大家供大家参考,具体如下:

#include<stdio.h>
#include<math.h>
struct complex_s{
    double x,y;
};
double real_part(struct complex_s z){
    return z.x;
}
double img_part(struct complex_s z){
    return z.y;
}
double magnitude(struct complex_s z){
    return sqrt(z.x*z.x + z.y*z.y);
}
double angle(struct complex_s z){
    return atan2(z.y, z.x);
}
struct complex_s make_from_real_img(double x, double y){
    struct complex_s z;
    z.x = x;
    z.y = y;
    return z;
}
struct complex_s make_from_mag_ang(double r, double A){
    struct complex_s z;
    z.x = r * cos(A);
    z.y = r * sin(A);
    return z;
}
struct complex_s add_complex(struct complex_s z1,struct complex_s z2){
    return make_from_real_img(real_part(z1)+real_part(z2),
        img_part(z1) + img_part(z2));
}
struct complex_s sub_complex(struct complex_s z1,struct complex_s z2){
    return make_from_real_img(real_part(z1)-real_part(z2),
        img_part(z1) - img_part(z2));
}
struct complex_s mul_complex(struct complex_s z1,struct complex_s z2){
    return make_from_mag_ang(real_part(z1)*real_part(z2),
        img_part(z1) + img_part(z2));
}
struct complex_s div_complex(struct complex_s z1,struct complex_s z2){
    return make_from_mag_ang(real_part(z1)/real_part(z2),
        img_part(z1) + img_part(z2));
}
int main(void){
    struct complex_s z1 = {3.0,4.0};
    struct complex_s z2= {2.0,5.0};
    struct complex_s x;
    x = add_complex(z1,z2);
    printf("x={%f,%f}",x.x,x.y);
    return 0;
}

结果:

[root@localhost struct]# ./jizuobiao.out
x={5.000000,9.000000}

希望本文所述对大家C语言程序设计有所帮助。

加载全部内容

相关教程
猜你喜欢
用户评论