php数据库操作Model类 php实现的简单数据库操作Model类
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本文实例讲述了php实现的简单数据库操作Model类。分享给大家供大家参考,具体如下:
该数据库模型类可实现数据库的增删改查,简化数据库操作。
1. config.php代码:
<?php define("HOSTNAME","127.0.0.1"); define("USERNAME","root"); define("PASSWORD",""); define("DATANAME","class");
2. 使用代码:
<?php /* 作者:shyhero */ require("./config.php"); class Model{ private $link; //构造函数,初始化数据库连接 public function __construct(){ $this -> link = mysqli_connect(HOSTNAME,USERNAME,PASSWORD,DATANAME) or die("数据库连接失败"); mysqli_set_charset($this -> link,"utf8"); } //查找 1.表名 2.条件 3.值 如果不添加条件或者值,就全部查询 public function find($table="",$key="",$value=""){ if(!$key||!$value){ $sql = "select * from {$table}"; }else{ $sql = "select * from {$table} where {$key} = '{$value}'"; } $res = mysqli_query($this -> link,$sql); $arr = mysqli_fetch_all($res,MYSQLI_ASSOC); mysqli_free_result($res); return $arr; } //增加 1.表名 2.需要插入的字段 3.值1 public function ins($table="",$zd="name,score",$value=""){ $arr = explode(",",$value); $str = ""; foreach($arr as $k => $v){ $str .= "'".$v."'".","; } $str = rtrim($str,","); $sql = "insert into {$table}({$zd})values({$str})"; $res = mysqli_query($this -> link,$sql); return mysqli_insert_id($this -> link); } //修改 1.表名 2.修改字段 3.值 4.条件 5.值 public function upd($table="",$key="",$value="",$key2="",$value2=""){ $sql = "update {$table} set {$key}='{$value}' where {$key2}='{$value2}'"; $res = mysqli_query($this -> link,$sql); return mysqli_affected_rows($this -> link); } //删除 1.表名 2.条件 3.值 public function del($table="",$key="",$value=""){ $sql = "delete from {$table} where {$key}='{$value}'"; $res = mysqli_query($this -> link,$sql); return mysqli_affected_rows($this -> link); } //析构函数 public function __destruct(){ if(isset($res)) mysqli_free_result($res); mysqli_close($this -> link); } } $m = new Model(); //var_dump($m -> find("stu","id")); var_dump($m -> ins("stu","name","zhu")); //var_dump($m -> upd("stu","name","dujianing","id","1")); //var_dump($m -> del("stu","name","li")); ?>
希望本文所述对大家PHP程序设计有所帮助。
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