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python中反射用法 python中反射用法实例

songguo 人气:0
想了解python中反射用法实例的相关内容吗,songguo在本文为您仔细讲解python中反射用法的相关知识和一些Code实例,欢迎阅读和指正,我们先划重点:python,反射,用法,下面大家一起来学习吧。

本文实例讲述了python中反射用法。分享给大家供大家参考。具体如下:

import sys, types,new
def _get_mod(modulePath):
  try:
    aMod = sys.modules[modulePath]
    if not isinstance(aMod, types.ModuleType):
      raise KeyError
  except KeyError:
    # The last [''] is very important!
    aMod = __import__(modulePath, globals(), locals(), [''])
    sys.modules[modulePath] = aMod
  return aMod
def _get_func(fullFuncName):
  """Retrieve a function object from a full dotted-package name."""
  # Parse out the path, module, and function
  lastDot = fullFuncName.rfind(u".")
  funcName = fullFuncName[lastDot + 1:]
  modPath = fullFuncName[:lastDot]
  aMod = _get_mod(modPath)
  aFunc = getattr(aMod, funcName)
  # Assert that the function is a *callable* attribute.
  assert callable(aFunc), u"%s is not callable." % fullFuncName
  # Return a reference to the function itself,
  # not the results of the function.
  return aFunc
def _get_Class(fullClassName, parentClass=None):
  """Load a module and retrieve a class (NOT an instance).
  If the parentClass is supplied, className must be of parentClass
  or a subclass of parentClass (or None is returned).
  """
  aClass = _get_func(fullClassName)
  # Assert that the class is a subclass of parentClass.
  if parentClass is not None:
    if not issubclass(aClass, parentClass):
      raise TypeError(u"%s is not a subclass of %s" %
              (fullClassName, parentClass))
  # Return a reference to the class itself, not an instantiated object.
  return aClass
def applyFuc(obj,strFunc,arrArgs):
  objFunc = getattr(obj, strFunc)
  return apply(objFunc,arrArgs)
def getObject(fullClassName):
  clazz = _get_Class(fullClassName)
  return clazz()
if __name__=='__main__':
  aa=getObject("inetservices.services.company.Company")  
  bb=applyFuc(aa, "select", ['select * from ngsys2',None])
  print bb

希望本文所述对大家的Python程序设计有所帮助。

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