python实现2048小游戏 python实现2048小游戏

# -*- coding: utf-8 -*-
"""
Created on Tue Jul 1 14:15:39 2014
 
@author: kelvin
"""
 
import random
 
class game2048:
 totalScore = 0
 v = [[2, 8, 8, 2],
   [4, 2, 4, 8],
   [2, 4, 2, 0],
   [4, 2, 4, 0]]
 '''
 v = [[0, 0, 0, 0],
   [0, 0, 0, 0],
   [0, 0, 0, 0],
   [0, 0, 0, 0]]
 '''
 def __init__(self):
  for i in range(4):
   self.v[i] = [random.choice([0,0,0,2,2,4]) for x in range(4)]
 
 
 def display(self):
  print('{0:4} {1:4} {2:4} {3:4}'.format(self.v[0][0], self.v[0][1], self.v[0][2], self.v[0][3]))
  print('{0:4} {1:4} {2:4} {3:4}'.format(self.v[1][0], self.v[1][1], self.v[1][2], self.v[1][3]))
  print('{0:4} {1:4} {2:4} {3:4}'.format(self.v[2][0], self.v[2][1], self.v[2][2], self.v[2][3]))
  print('{0:4} {1:4} {2:4} {3:4}'.format(self.v[3][0], self.v[3][1], self.v[3][2], self.v[3][3]))
  print('得分为:{0:4}'.format(self.totalScore))
  print('游戏是否结束:{0:4}'.format(self.isOver()))
 #重新排列
 def align(self,vList, direction):
  for i in range(vList.count(0)):
   vList.remove(0)
  zeros = [0 for x in range(4-len(vList))]
  if direction == 'left':
   vList.extend(zeros)
  else:
   vList[:0] = zeros
 #将相同的元素相加，返回新增积分
 def addSame(self,vList, direction):
  increment=0
  if direction == 'left':
   for i in [0,1,2]:
    if vList[i]==vList[i+1] and vList[i+1]!=0:
     vList[i] *= 2
     vList[i+1] = 0
     increment += vList[i]
  else:
   for i in [3,2,1]:
    if vList[i]==vList[i-1] and vList[i-1]!=0:
     vList[i] *= 2
     vList[i-1] = 0
     increment += vList[i]
  return increment
 #处理行和方向,返回新增积分
 def handle(self, vList, direction):
  self.align(vList, direction)
  increment = self.addSame(vList, direction)
  self.align(vList, direction)
  self.totalScore += increment #直接加到总值
  return increment
 #判断游戏是否结束
 def judge(self):
   
  if self.isOver():
   print('你输了，游戏结束!')
   return False
  else:
   if self.totalScore >= 2048:
    print('你赢了，游戏结束！但是你还可以继续玩。')
   return True
 #判断游戏是否真正结束
 def isOver(self):
  N = self.calcCharNumber(0)
  if N!=0:
   return False
  else:
   for row in range(4):
    flag = self.isListOver(self.v[row])
    if flag==False:
     return False 
   for col in range(4):
    # 将矩阵中一列复制到一个列表中然后处理
    vList = [self.v[row][col] for row in range(4)]
    flag = self.isListOver(vList)
    if flag==False:
     return False
  return True
  
 #判断一个列表是否还可以合并
 def isListOver(self, vList):
  for i in [0,1,2]:
   if vList[i]==vList[i+1] and vList[i+1]!=0:
    return False
  return True
 def calcCharNumber(self, char):
  n = 0
  for q in self.v:
   n += q.count(char)
  return n
 def addElement(self):
  # 统计空白区域数目 N
  N = self.calcCharNumber(0)
  if N!=0:
   # 按2和4出现的几率为3/1来产生随机数2和4
   num = random.choice([2, 2, 2, 4]) 
   # 产生随机数k，上一步产生的2或4将被填到第k个空白区域
   k = random.randrange(1, N+1) #k的范围为[1,N]
   n = 0
   for i in range(4):
    for j in range(4):
     if self.v[i][j] == 0:
      n += 1
      if n == k:
       self.v[i][j] = num
       return
 
     
 def moveLeft(self):
  self.moveHorizontal('left')
 def moveRight(self):
  self.moveHorizontal('right')
 def moveHorizontal(self, direction):
  for row in range(4):
   self.handle(self.v[row], direction)
 
 def moveUp(self):
  self.moveVertical('left')
 def moveDown(self):
  self.moveVertical('right')
 def moveVertical(self, direction):
  for col in range(4):
   # 将矩阵中一列复制到一个列表中然后处理
   vList = [self.v[row][col] for row in range(4)]
   self.handle(vList, direction)
   # 从处理后的列表中的数字覆盖原来矩阵中的值
   for row in range(4):
    self.v[row][col] = vList[row]
     
 #主要的处理函数
 def operation(self):
  op = input('operator:')
  if op in ['a', 'A']: # 向左移动
   self.moveLeft()
   self.addElement()
  elif op in ['d', 'D']: # 向右移动
   self.moveRight()
   self.addElement()
  elif op in ['w', 'W']: # 向上移动
   self.moveUp()
   self.addElement()
  elif op in ['s', 'S']: # 向下移动
   self.moveDown()
   self.addElement()
  else:
   print('错误的输入。请输入 [W, S, A, D] 或者是其小写') 
 
#开始
print('输入：W(上移) S(下移) A(左移) D(右移), press <CR>.')
g =game2048()
flag = True
while True:
 g.display()
 flag = g.judge()
 g.operation()
 flag = g.judge()