Python单例模式实例 Python设计模式之单例模式实例
人气:0注：使用的是Python 2.7。
一个简单实现
class Foo(object):
__instance = None
def __init__(self):
pass
@classmethod
def getinstance(cls):
if(cls.__instance == None):
cls.__instance = Foo()
return cls.__instance
if __name__ == '__main__':
foo1 = Foo.getinstance()
foo2 = Foo.getinstance()
print id(foo1)
print id(foo2)
print id(Foo())
输出的前两个结果是相同的（id(foo1)与id(foo2)的值相同），第三个结果和前两个不同。这里类方法getinstance()用于获取单例，但是类本身也可以实例化，这样的方式其实并不符合单例模式的要求。但是这样做也有好处，代码简单，大家约定好这样子调用就行了。但是最好在类的命名上也体现了出来这是一个单例类，例如Foo_singleton。
换一个思路
先说一下init和new的区别：
class Foo(object):
__instance = None
def __init__(self):
print 'init'
if __name__ == '__main__':
foo = Foo()
运行结果是：
init
而下面的示例：
class Foo(object):
__instance = None
def __init__(self):
print 'init'
def __new__(cls, *args, **kwargs):
print 'new'
if __name__ == '__main__':
foo = Foo()
运行结果是：
new是一个类方法，会创建对象时调用。而init方法是在创建完对象后调用，对当前对象的实例做一些一些初始化，无返回值。如果重写了new而在new里面没有调用init或者没有返回实例,那么init将不起作用。以下内容引用自http://docs.python.org/2/reference/datamodel.html#object.new
If __new__() returns an instance of cls, then the new instance's __init__() method will be invoked like __init__(self[, ...]), where self is the new instance and the remaining arguments are the same as were passed to __new__().
If __new__() does not return an instance of cls, then the new instance's __init__() method will not be invoked.
这样做：
class Foo(object):
__instance = None
def __init__(self):
print 'init'
def __new__(cls, *args, **kwargs):
print 'new'
if cls.__instance == None:
cls.__instance = cls.__new__(cls, *args, **kwargs)
return cls.__instance
if __name__ == '__main__':
foo = Foo()
错误如下：
RuntimeError: maximum recursion depth exceeded in cmp
而这样也有一样的错误：
class Foo(object):
__instance = None
def __init__(self):
if self.__class__.__instance == None:
self.__class__.__instance = Foo()
print 'init'
if __name__ == '__main__':
foo = Foo()
该怎么做呢？
下面参考了http://stackoverflow.com/questions/31875/is-there-a-simple-elegant-way-to-define-singletons-in-python/31887#31887：
class Foo(object):
__instance = None
def __new__(cls, *args, **kwargs):
print 'hhhhhhhhh'
if not cls.__instance:
cls.__instance = super(Foo, cls).__new__(cls, *args, **kwargs)
return cls.__instance
def hi(self):
print 'hi, world'
print 'hi, letian'
if __name__ == '__main__':
foo1 = Foo()
foo2 = Foo()
print id(foo1)
print id(foo2)
print isinstance(foo1, object)
print isinstance(foo1, Foo)
foo1.hi()
运行结果：
hhhhhhhhh
hhhhhhhhh
39578896
39578896
True
True
hi, world
hi, letian
那么，到底发生了什么，我们先回顾一下super：
>>> print super.__doc__
super(type) -> unbound super object
super(type, obj) -> bound super object; requires isinstance(obj, type)
super(type, type2) -> bound super object; requires issubclass(type2, type)
Typical use to call a cooperative superclass method:
class C(B):
def meth(self, arg):
super(C, self).meth(arg)
可以肯定上面的单例模式代码中的这一行代码：
cls.__instance = super(Foo, cls).__new__(cls, *args, **kwargs)
super(Foo, cls)是object，super(Foo, cls).new方法使用的是object的new方法。我们看一下object.new方法的作用：
>>> print object.__new__.__doc__
T.__new__(S, ...) -> a new object with type S, a subtype of T
如果是一个继承链
class Fo(object):
def __new__(cls, *args, **kwargs):
print 'hi, i am Fo'
return super(Fo, cls).__new__(cls, *args, **kwargs)
class Foo(Fo):
__instance = None
def __new__(cls, *args, **kwargs):
if not cls.__instance:
print Foo is cls
print issubclass(cls, Fo)
print issubclass(cls, object)
cls.__instance = super(Foo, cls).__new__(cls, *args, **kwargs)
return cls.__instance
def hi(self):
print 'hi, world'
if __name__ == '__main__':
foo1 = Foo()
foo1.hi()
print isinstance(foo1, Foo)
print isinstance(foo1, Fo)
print isinstance(foo1, object)
运行结果如下：
True
True
True
hi, i am Fo
hi, world
True
True
True
如果如下定义Fo，也正常运行：
class Fo(object):
pass
但是，若这样定义：
class Fo(object):
def __new__(cls, *args, **kwargs):
print 'hi, i am Fo'
运行时报错如下：
AttributeError: 'NoneType' object has no attribute 'hi'
加载全部内容