ASP发送和接收XML 利用ASP发送和接收XML数据的处理方法

dim Https
set Https=server.createobject("MSXML2.XMLHTTP")
'定义一个XMLHTTP对像
Https.open "POST","http://127.0.0.1/testpost/response.asp",false
Https.send " echo
123456 987654
11111 22222 "
if Https.readystate=4 then
　response.write "提交成功"
　'readstate读取状态为4则成功，继续后面的，不成功当然就不用继续处理了
　dim objstream
　set objstream = Server.CreateObject("adodb.stream")
　'定义一个stream，因为读过来的直接拿出来是乱码的，所以得处理一下
　objstream.Type = 1
　objstream.Mode =3
　objstream.Open
　objstream.Write Https.responseBody
　objstream.Position = 0
　objstream.Type = 2
　objstream.Charset = "GB2312"
　html = objstream.ReadText
　'转好码，就放到html里，好关闭这些对像
　objstream.Close
　set objstream = nothing
　set https=nothing
end if
response.write html

response.asp

'创建DOMDocument对象
Set xml = Server.CreateObject ("msxml2.DOMDocument")
xml.async = False

'装载POST数据
xml.Load Request
If xml.parseError.errorCode <> 0 Then
　response.write "不能正确接收数据" & "Description: " & xml.parseError.reason & "＜br＞Line: " & xml.parseError.Line
End If

set blogchild=xml.getElementsByTagName("misc_command")
'the_text=blogchild.item(0).childnodes(1).text
'the_text=blogchild.item(0).text
'for i=0 to blogchild.length-1
response.write the_text