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JavaScript实现构造json数组的方法分析

枫轩缘 人气:0

本文实例讲述了JavaScript实现构造json数组的方法。分享给大家供大家参考,具体如下:

从后端拿到的数据是一个数组,每个元素中包含的数据如下(host相同的记录都是相邻的)

currentTime:"1470729601"
host:"10.3.34.21"
taskList:null
taskNum:1

想构造类似如下结构的json数组

[{
  name: 'host:10.1.6.49',
  data: [
    [1470641461000, 5],
    [1470642581000, 4],
    [1470643701000, 2],
    [1470647341000, 3]
  ]
}, {
  name: 'host:10.3.34.18',
  data: [
    [1470641461000, 2],
    [1470642581000, 2],
    [1470643701000, 1],
    [1470647341000, 4]
  ]
}, {
  name: 'host:10.2.2.22',
  data: [
    [1470641461000, 3],
    [1470642581000, 2],
    [1470643701000, 6],
    [1470647341000, 4]
  ]
},{
  name: 'host:10.1.110.96',
  data: [
    [1470641461000, 1],
    [1470642581000, 8],
    [1470643701000, 1],
    [1470647341000, 1]
  ]
},{
  name: 'host:10.2.2.87',
  data: [
    [1470641461000, 7],
    [1470642581000, 3],
    [1470643701000, 6],
    [1470647341000, 5]
  ]
}]

错误的方式:

var backendData = data.result;
var resultList = new Array();
var curHost = "";
var oneHostDataList = new Array();
for (var i in backendData) {
  var host = backendData[i].host;
  if (host != curHost) {
    if(i != 0) {
      var item = new Object();
      item.name = curHost;
      item.data = oneHostDataList;
      resultList.push(item);
    }
    oneHostDataList = new Array();
    curHost = host;
  }
  else {
    var dot = new Array();
    dot.push(backendData[i].currentTime * 1000);
    dot.push(backendData[i].taskNum);
    oneHostDataList.push(dot);
  }
}
var item = new Object();
item.name = curHost;
item.data = oneHostDataList;
resultList.push(item);
$scope.data = JSON.stringify(resultList);

以上方式的问题在于转换后会使得name和host和带上引号,正确的方式如下:

var backendData = data.result;
var resultList = [];
var curHost = "";
var oneHostDataList = new Array();
for (var i in backendData) {
  var host = backendData[i].host;
  if (host != curHost) {
    if(i != 0) {
      var item = {
        name: curHost,
        data: oneHostDataList
      };
      resultList.push(item);
    }
    oneHostDataList = new Array();
    curHost = host;
  }
  else {
    var dot = new Array();
    dot.push(backendData[i].currentTime * 1000);
    dot.push(backendData[i].taskNum);
    oneHostDataList.push(dot);
  }
}
var item = new Object();
item.name = curHost;
item.data = oneHostDataList;
resultList.push(item);
$scope.data = resultList;

PS:这里再为大家推荐几款相关的json在线工具供大家参考:

在线JSON代码检验、检验、美化、格式化工具:
http://tools.softyun.net/code/json

JSON在线格式化工具:
http://tools.softyun.net/code/jsonformat

在线XML/JSON互相转换工具:
http://tools.softyun.net/code/xmljson

json代码在线格式化/美化/压缩/编辑/转换工具:
http://tools.softyun.net/code/jsoncodeformat

在线json压缩/转义工具:
http://tools.softyun.net/code/json_yasuo_trans

希望本文所述对大家JavaScript程序设计有所帮助。

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