Python利用tkinter和socket实现端口扫描
所谓独醉 人气:0题目
请设计并实现一款主机端口扫描程序。程序根据用户输入的域名或IP地址,可以查询该主机的开放的端口号。 例如:
并有一定的异常处理
参考code
import tkinter from tkinter import * import socket import tkinter.messagebox class CheckPort: def __init__(self): window = Tk() window.title("端口扫描") window.geometry("600x500") frame1 = Frame(window) frame1.pack() Label(frame1, text="IP地址、域名:", bg="#f0f0f0").grid(row=0, column=1, pady=3) Label(frame1, text="起始端口(最小为1):", bg="#f0f0f0").grid(row=1, column=1, pady=3) Label(frame1, text="结束端口(最大为65535):", bg="#f0f0f0").grid(row=2, column=1, pady=3) self.searchText = StringVar() Entry(frame1, textvariable=self.searchText, justify=LEFT).grid(row=0, column=2) self.originPort = IntVar() Entry(frame1, textvariable=self.originPort, justify=LEFT).grid(row=1, column=2) self.endPort = IntVar() Entry(frame1, textvariable=self.endPort, justify=LEFT).grid(row=2, column=2) Button(frame1, text="扫描", command=self.getRes).grid(row=3, column=1, columnspan=2, pady=3) frame2 = Frame(window).pack() self.resText = Text(frame2, height=50, width=500, wrap=WORD) self.resText.pack() window.mainloop() def getRes(self): try: ip = socket.gethostbyname(self.searchText.get()) str1 = "" if 1 <= self.originPort.get() <= self.endPort.get() <= 65535: for port in range(self.originPort.get(), self.endPort.get() + 1): try: socket.setdefaulttimeout(1) client = socket.socket() client.connect((ip, port)) client.shutdown(1) str1 += f"{ip}:{port}已开放\n" except Exception as e: str1 += f"{ip}:{port}未开放\n" pass str1 += f"扫描完成\n" self.resText.insert(END, str1) else: self.errorHandle("请输入正确的端口号!") except: self.errorHandle("请输入正确的域名或者ip地址!") def errorHandle(self, message): tkinter.messagebox.showerror(title="error", message=message) CheckPort()
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